Calculate the volume of CO2 evolved by the combustion of 50 ml of a mixture contains C2H4 and 60% CH4 (by volume)

Calculate the volume of CO2 evolved by the combustion of 50 ml of a mixture contains C2H4 and 60% CH4 (by volume)

Solution=
50 ml mixture of C2H4 and CH4,

where CH4=50% of 60ml=30ml and C2H4=20ml.

applying limiting reagent law

C2H4 +CH4+5O2⟶3CO2+4H2O

(20−x) (30−x)3x
limiting reagent is C2H4

∴(20−x)=0 and x=20
putting the value of x for CO2
The volume of CO2=3x=3×20=60ml